X^2+(x+4)=480

Solution for X^2+(x+4)=480 equation:

X^2+(X+4)=480

We move all terms to the left:

X^2+(X+4)-(480)=0

We get rid of parentheses

X^2+X+4-480=0

We add all the numbers together, and all the variables

X^2+X-476=0

a = 1; b = 1; c = -476;
Δ = b2-4ac
Δ = 12-4·1·(-476)
Δ = 1905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1905}}{2*1}=\frac{-1-\sqrt{1905}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1905}}{2*1}=\frac{-1+\sqrt{1905}}{2}
$